Integrand size = 22, antiderivative size = 29 \[ \int \frac {1}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=\frac {i}{d (a \cos (c+d x)+i a \sin (c+d x))} \]
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Time = 0.02 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.045, Rules used = {3150} \[ \int \frac {1}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=\frac {i}{d (a \cos (c+d x)+i a \sin (c+d x))} \]
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Rule 3150
Rubi steps \begin{align*} \text {integral}& = \frac {i}{d (a \cos (c+d x)+i a \sin (c+d x))} \\ \end{align*}
Time = 0.25 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00 \[ \int \frac {1}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=\frac {i}{d (a \cos (c+d x)+i a \sin (c+d x))} \]
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Time = 0.40 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.66
method | result | size |
risch | \(\frac {i {\mathrm e}^{-i \left (d x +c \right )}}{a d}\) | \(19\) |
derivativedivides | \(\frac {2}{d a \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-i\right )}\) | \(23\) |
default | \(\frac {2}{d a \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-i\right )}\) | \(23\) |
norman | \(\frac {-\frac {2 i \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{a d}+\frac {2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{a d}}{1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}\) | \(55\) |
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none
Time = 0.24 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.59 \[ \int \frac {1}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=\frac {i \, e^{\left (-i \, d x - i \, c\right )}}{a d} \]
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Time = 0.07 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.07 \[ \int \frac {1}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=\begin {cases} \frac {i e^{- i c} e^{- i d x}}{a d} & \text {for}\: a d e^{i c} \neq 0 \\\frac {x e^{- i c}}{a} & \text {otherwise} \end {cases} \]
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none
Time = 0.22 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00 \[ \int \frac {1}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=\frac {2}{{\left (-i \, a + \frac {a \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )} d} \]
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none
Time = 0.27 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.72 \[ \int \frac {1}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=\frac {2}{a d {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - i\right )}} \]
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Time = 22.59 (sec) , antiderivative size = 25, normalized size of antiderivative = 0.86 \[ \int \frac {1}{a \cos (c+d x)+i a \sin (c+d x)} \, dx=\frac {2{}\mathrm {i}}{a\,d\,\left (1+\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,1{}\mathrm {i}\right )} \]
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